wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Question 2
The triangular side walls of a flyover have been used for advertisement. The sides of the walls are 122m, 22m, and 120m (see the given figure). The advertisements yield an earning of Rs 5000 per
m2 per year. A company hired one of its walls for 3 months. How much rent did it pay?

Open in App
Solution

The sides of the triangle (i.e., a,b,c) are of 122m, 22m, and 120m respectively.
Perimeter of triangle = ( 122+22+120) m

2s = 264m
S = 132m

By Heron’s formula,
Area of triangle = s(sa)(sb)(sc)
Area of given triangle=132(132122)(13222)(132120) m2
=132(10)(110)(12) m2=1320 m2
Rent of 1 m2 area per year = Rs 5000
Rent of 1 m2 area per month = Rs500012
Rent of 1320 m2 area for 3 months = Rs(500012×3×1320)=Rs(5000×330)=Rs1650000

Therefore, the company has to pay Rs 1650000.


flag
Suggest Corrections
thumbs-up
19
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon