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Question

# Question 2 The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 13m, 14m and 15m. the advertisements yield an earning of Rs.2000 per m2 a year. A company hired one of its walls for 6 mnoths. How much rent did it pay?

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Solution

## Given that the sides of the triangular walls are a = 13m, b = 14m and c = 15m ∴ semi-perimeter of triangular side wall, s=a+b+c2 =13+14+152=422=21m ∴ Area of triangular side wall =√s(s−a)(s−b)(s−c) [by Heron’s formula] =√21(21−13)(21−14)(21−15) =√21×8×7×6 =√21×4×2×7×3×2 =√(21)2×(4)2=21×4=84m2 The advertisement yield earning per year for 1 m2 = Rs. 2000 ∴ The advertisement yield earning per year on 84 m2 = 2000 × 84 = Rs.168000 As the company hired one of its walls for 6 months, therefore company pay the rent =12(168000)=Rs 84000 Hence, the company paid Rs.84000 as the rent.

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