Question

The true value of angle of dip at a place is ${60}^o$ , the apparent dip in a plane inclined at an angle of ${30}^o$ with magnetic meridian is

• A. $ta{n}^{-1}\frac{1}{2}$
• B. $ta{n}^{-1}\left(2\right)$
• C. $ta{n}^{-1}\left(\frac{2}{3}\right)$
• D. None of these

Answer 1

Answer: (B)

$ta{n}^{-1}\left(2\right)$

We know that $tan\psi =\frac{tan\varphi }{cos\beta };where\psi$= apparent angle of dip,

$\varphi$ = true angle of dip $\beta$ = angle made by vertical plane with magnetic meridian .

$\Rightarrow tan\psi =\frac{tan{60}^0}{cos{30}^0}=2\Rightarrow \psi =ta{n}^{-1}\left(2\right)$