Question

The true value of dip at a place is ${45}^o$. If the place of the dip circle is turned through ${60}^o$ from the magnetic meridian, the apparent value of dip will be

• A. ${\tan }^{-1}\left(2\right)$
• B. ${30}^o$
• C. ${45}^o$
• D. ${\tan }^{-1}\left(5\right)$

Answer 1

The correct option is A ${\tan }^{-1}\left(2\right)$

Given: True dip$\left(\varphi \right)={45}^0$ ,dip circle is turned through$\theta ={60}^0$

Solution: Here we can use the direct formula i.e.

$tan{\varphi }^{{}^{\prime }}=\frac{tan\varphi }{cos\theta }$

Where ,

$tan{\varphi }^{{}^{\prime }}$=apparent dip

$tan\varphi$=true dip

$cos\theta$=angle turned from dip circle

Now putting values$tan{\varphi }^{{}^{\prime }}=\frac{tan{45}^0}{cos{60}^0}$

$tan{\varphi }^{{}^{\prime }}=2$

Hence the correct option is A