The type of hybridization of boron in diborane is :

s p

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s p^{2}

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s p^{3}

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s p^{3} d^{2}

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Solution

The correct option is D $s p^{3}$
The hybridization of $B_{2} H_{6}$ (diborane) is $s p^{3}$ because each boron molecule has a tetrahedral geometry.
Hence option C is correct

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Similar questions

The type of hybridisation of boron in diborane is

(a) sp (b) sp²(c) sp³ (d) dsp²

C H_{4}, C_{2} H_{6}, a n d C_{2} H_{4}

s p, s p^{2} a n d s p^{3}

Question 03

The types of hybrid orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}$ respectively are expected to be

(a) $s p, s p^{3} a n d s p^{2}$

(b) $s p, s p^{2} a n d s p^{3}$

(d) $s p^{2}, s p^{3} a n d s p$

(C_{3} H_{4})

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