Question

The uncertainty of a particle in momentum is $3.3\times {10}^{-2}$ $kg$ $m{s}^{-1}$. Calculate the uncertainty in its position. $(h=6.6\times {10}^{-34}J-sec)$.

• A. $1.1\times {10}^{-14}m$
• B. $1.59\times {10}^{-33}m$
• C. $3.1\times {10}^{-14}cm$
• D. none of these

Answer 1

The correct option is B $1.59\times {10}^{-33}m$

According to uncertainty principle

$\Delta x.\Delta p=>h/4\pi$

Putting the values

$\Delta x=\frac{6.6\times {10}^{-34}}{4\times 3.14\times (3.3\times {10}^{-2})}$

$\Delta x=1.59\times {10}^{-33}m$