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Question

The value of (0.16)log2.5(13+132+) is 


Solution

13+132+
=1/311/3=12

(0.16)log2.5(13+132+)
=[(0.4)2]log5/212
=(0.4)log5/214
=(14)log5/225     (alogbc=clogba)
=(4)log5/225
=(4)log2/525
=4

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