wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of (103)2 using identity is.

A
10609
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
10906
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
10606
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10806
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 10609
We know that,
(a+b)2=a2+b2+2ab

Now,
103 can be written as (100+3).
On applying the identity (a+b)2 and
considering, a = 100 and b = 3,

(103)2
=1002+32+2×100×3
=10609

flag
Suggest Corrections
thumbs-up
32
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon