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Question

The value of (109)2 is _______.


A

11881

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B

10881

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C

11891

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D

11880

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Solution

The correct option is A

11881


109=100+9

Using the identity:
(a+b)2= (a)2+2×a×b+(b)2,
(100+9)2=(100)2+2×100×9+(9)2
=10000+1800+81
=11881


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