CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The value of $$32 cot^2\frac{\pi}{4} - 8 sec^2 \frac{\pi}{3} + 8 {cos}^3 \frac{\pi}{6}$$ is equal to:


A
33
loader
B
23
loader
C
3
loader
D
63
loader

Solution

The correct option is A $$3\sqrt 3$$
$$\rightarrow 32{ cot }^{ 2 }\left( \pi /4 \right) -8{ sec }^{ 2 }\left( \pi /3 \right) +8{ cos }^{ 3 }\left( \pi /6 \right) $$
$$\rightarrow 32{ \left( 1 \right)  }^{ 2 }-8{ \left( 2 \right)  }^{ 2 }+8{ \left( \dfrac { \sqrt { 3 }  }{ 2 }  \right)  }^{ 3 }=32-8\left( 4 \right) +3\sqrt { 3 } $$
$$\rightarrow 3\sqrt { 3 } $$

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image