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Question

The value of
4[1sin2θ][1+tan2θ]


A

4

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B

1

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C

2

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D

0

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Solution

The correct option is A

4


Weknowthat(1sin2θ=cos2θand 1+tan2θ=sec2θ)

4[1sin2θ][1+tan2θ] =4 cos2θ×sec2θ=4


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