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Question

The value of  [6 × P + 2 ]is , if it is given that

    3 1 P

+  1 P 3
    ____

    5 0 1


  1. 20
  2. 60
  3. 80
  4. 50


Solution

The correct options are
C 80
D 50

For ones digit, 8 + 3 = 1 
P = 8 and 1 is carried over.

Verification:

For tens digit, 1(carryover) + 1 + 8 = 10

For hundreds digit, 3 + 1 + 1(carry over) = 5

Therefore value of P is 8.
Value of  6 x P + 2 = 6 x 8 + 2 
= 48 + 2 = 50

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