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Question

The value of ′c′ such that the line joining (0,3),(5,−2) is a tangent to the curve y=cx+1

A
4
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B
3
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C
23
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D
1
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Solution

The correct option is C 23
Given equation of curve is y=cx+1
dydx=c(x+1)2
Slope of tangent to curve =c(x+1)2
Equation of tangent line joining (0,3) and (5,-2) is
y=x+3.
c(x+1)2=1
c=(x+1)2
Equation of curve becomes y=x+1
x+3=x+1
x=1
c=4

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