Equation of Tangent at a Point (x,y) in Terms of f'(x)
The value of ...
Question
The value of ′c′ such that the line joining (0,3),(5,−2) is a tangent to the curve y=cx+1
A
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
23
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C23 Given equation of curve is y=cx+1 dydx=−c(x+1)2 Slope of tangent to curve =−c(x+1)2 Equation of tangent line joining (0,3) and (5,-2) is y=−x+3. ⇒−c(x+1)2=−1 ⇒c=(x+1)2 Equation of curve becomes y=x+1 −x+3=x+1 ⇒x=1 ⇒c=4