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Byju's Answer
Standard XII
Mathematics
Trigonometric Ratios of Compound Angles
The value of ...
Question
The value of
cos
52
0
+
cos
68
∘
+
cos
172
0
,
is
A
0
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B
1
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C
2
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D
None of these
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Solution
The correct option is
A
0
c
o
s
52
∘
+
c
o
s
68
∘
+
c
o
s
172
∘
⇒
c
o
s
52
∘
+
2
c
o
s
(
68
+
172
2
)
c
o
s
(
172
−
68
2
)
[
c
o
s
C
+
c
o
s
D
=
2
c
o
s
(
C
+
D
2
)
c
o
s
(
C
−
D
2
)
]
⇒
c
o
s
52
∘
+
2
c
o
s
(
120
)
∘
c
o
s
(
104
2
)
∘
⇒
c
o
s
52
∘
[
1
+
2
c
o
s
(
120
)
]
⇒
c
o
s
52
∘
[
1
+
2
c
o
s
(
180
−
60
)
]
⇒
c
o
s
52
∘
[
1
−
2
c
o
s
60
∘
]
⇒
c
o
s
2
∘
[
1
−
2
(
1
2
)
]
⇒
0
∴
c
o
s
52
∘
+
c
o
s
68
∘
+
c
o
s
172
∘
=
0
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0
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Q.
The value of cos 1° cos 2° cos 3° ..... cos 180° is
(a) 1
(b) 0
(c) −1
(d) None of these