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Question

The value of determinant ∣ ∣b+cabac+abcba+bcac∣ ∣ is

A
a3+b3+c33abc
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B
(a3+b3+c33abc)
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C
(a3+b3+c3)
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D
None of these
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Solution

The correct option is B (a3+b3+c33abc)
Let Δ=∣ ∣b+cabac+abcba+bcac∣ ∣

Applying C1C1+C3,C2C2C3, we get
Δ=∣ ∣a+b+cbaa+b+ccba+b+cac∣ ∣=(a+b+c)∣ ∣1ba1cb1ac∣ ∣

Applying R2R2R1,R3R3R1, we get
Δ=(a+b+c)∣ ∣1ba0cbba0abca∣ ∣=(a+b+c)(a2+b2+c2abbcca)=(a3+b3+c33abc)

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