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Question

The value of 2sin2x2sin2x+cos2xdx is
(where C is integration constant)

A
22sin2x+cos2x+C
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B
42sin2x+cos2x+C
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C
4sin2x+2cos2x+C
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D
2sin2x+2cos2x+C
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Solution

The correct option is B 42sin2x+cos2x+C
Let I=2sin2x2sin2x+cos2xdx
Put 2sin2x+cos2x=t,sin2xdx=dt
I=2t12dtI=4t+C =42sin2x+cos2x+C

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