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Question

The value of :

π2π2(x3+xcosx+tan5x+1) dx

A
0
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B
2
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C
π
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D
1
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Solution

The correct option is D π
Let I=π/2π/2(x3+xcosx+tan5x+1) dx

We know,
If f(x) is an even function, then aaf(x) dx=2a0f(x) dx

If f(x) is an odd function, then aaf(x) dx=0

Thus, I=0+0+0+2π/20dx

I=2[x]π/2o=2π2=π

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