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Byju's Answer
Standard XII
Mathematics
Differentiation under Integral Sign
The value of ...
Question
The value of
lim
m
→
∞
(
cos
x
m
)
m
is
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Solution
lim
m
→
∞
(
cos
x
m
)
m
,
[
1
∞
form
]
=
e
lim
m
→
∞
m
(
cos
x
m
−
1
)
=
e
lim
m
→
∞
m
(
−
2
sin
2
x
2
m
)
=
e
lim
m
→
∞
−
2
m
(
x
/
2
m
)
2
⎛
⎜ ⎜
⎝
sin
2
x
2
m
(
x
/
2
m
)
2
⎞
⎟ ⎟
⎠
=
e
lim
m
→
∞
−
x
2
2
m
=
e
0
=
1
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11
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Differentiation under Integral Sign
Standard XII Mathematics
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