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Question

The value of 10n=12n2n1sin27x dx+10n=12n+12nsin27x dx is equal to 
  1. 0
  2. 27
  3. 54
  4. 54


Solution

The correct option is A 0
Let I1=10n=12n2n1sin27x dx,
I2=10n=12n+12nsin27x dx

I1=10n=12n2n1sin27x dx,
Let x=tdx=dt
I1=10n=12n2n+1sin27(t)(dt)
I1=10n=12n2n+1sin27x dx
I1=10n=12n+12nsin27x dx
I1=I2I1+I2=0
 

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