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Question

The value of 19r=120Cr+1(1)r22r+1 is


A
2((34)20+4)
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B
2((34)20+4)
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C
2((34)204)
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D
2((34)204)
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Solution

The correct option is B 2((34)20+4)
19r=120Cr+1(1)r22r+1
=1219r=1 20Cr+1(14)r
=1220r=2 20Cr(14)r1
=220r=220Cr(14)r
=2[(114)20(20C0(14)0+20C1(14)1)]
=2((34)20+4)
 

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