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Question

The value of limθ01cos4θ1cos6θ is 
  1. 49
  2. 94
  3. 93
  4. 34


Solution

The correct option is A 49
limθ01cos4θ1cos6θ
=limθ01cos4θ1cos6θ×1+cos4θ1+cos4θ×1+cos6θ1+cos6θ
=limθ0sin24θsin26θ
=4262×(limθ0sin4θ4θ)2×(limθ06θsin6θ)2
=49

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