The value of expression 1-82-0-52 is

The correct option is B 0.81 The given expression is (1.8)^2 × (0.5)^2 (1.8)^2 × (0.5)^2 =(1.8 × 0.5)^2 [x^2 y^2=(xy)^2] =(0.9)^2 = ( 9/10 ) × ( 9/10 ) ...

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Standard VII

Mathematics

Observing Length and Breadth of Rectangles of Squares Using Dot Grids

The value of ...

Question

The value of expression $(1.8)^{2} \times (0.5)^{2}$ is

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0.81

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0.081

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8.1

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Solution

The correct option is B
0.81

The given expression is $(1.8)^{2} \times (0.5)^{2}$

$(1.8)^{2} \times (0.5)^{2}$

$= (1.8 \times 0.5)^{2} [x^{2} y^{2} = (x y)^{2}]$

$= (0.9)^{2}$

$= (\frac{9}{10}) \times (\frac{9}{10})$

$= \frac{81}{100} = 0.81$

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The value of expression (1.8)2×(0.5)2 is

The correct option is B 0.81 The given expression is (1.8)2×(0.5)2 (1.8)2×(0.5)2 =(1.8×0.5)2 [x2y2=(xy)2] =(0.9)2 =(910)×(910) =81100=0.81

The value of expression $(1.8)^{2} \times (0.5)^{2}$ is

The correct option is B
0.81

The given expression is $(1.8)^{2} \times (0.5)^{2}$

$(1.8)^{2} \times (0.5)^{2}$

$= (1.8 \times 0.5)^{2} [x^{2} y^{2} = (x y)^{2}]$

$= (0.9)^{2}$

$= (\frac{9}{10}) \times (\frac{9}{10})$

$= \frac{81}{100} = 0.81$