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Question

The value of expression 
3(1!)4(2!)+5(3!)6(4!)+.....2008(2006!)+(2007!) is


Your Answer
A
2007
Your Answer
B
1
Correct Answer
C
1
Your Answer
D
2007

Solution

The correct option is D 1
T1=3(1!)=(2+1)(1!)=2!+1!T2=(3+1)(2!)=3!2!T3=(4+1)(3!)=4!+3!T4=(5+1)(4!)=5!4!...T2006=(2007+1)(2006!)=2007!2006!
So the sum of all the terms will be ,
T1+T2+.......T2006=2007!+1
So the value of expression =1

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