CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The value of π0cos3 θcos θ+sin θd θ is


Your Answer
A
π4
Your Answer
B
π6
Correct Answer
C
π2
Your Answer
D
π3

Solution

The correct option is C π2
I=π0cos 3θcos θ+sin θdθ=π0cos3(πθ)cos(πθ)+sin(πθ)dθ

I=π0cos3θcos θsin θd θ

Adding, 2I=π02cos 3 θ cos θcos2θd θ

π0cos4 θ+cos2 θcos2 θd θ

=2π20cos4 θcos2 θd θ+π

I1=π20cos4 θcos2 θd θ=π20cos(2π4 θ)cos(π2 θ)d θ=I1

I2=0. Hence 2I=π or I=π2
 

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image