Question

The value of $k$ for which $4x^2-4\sqrt{3}x+k=0$ is satisfied by only one real value of $x$ is

• A. $\sqrt{6}$
• B. $-3$
• C. $3$
• D. $\frac{1}{\sqrt{3}}$

Answer 1

The correct option is C $3$

We know that $(a-b{)}^2=a^2-2ab+b^2$
Given Equation is $4x^2-4\sqrt{3}x+k$
Co-pairing both equations, we get
$a=2x$ and $k=3$