The value of k for which the points A(2,3),B(4,k), and C(6,−3) are collinear.
The correct option is C: k=0
Given three points are A(2,3),B(4,k), and C(6,−3).
When the points are collinear, the area of the triangle will be zero.
Area of the triangle =12[x1(y2−y1)+x2(y3−y1)+x3(y1−y2)]
The points are collinear.
⇒|−2k|=0 [Area cannot be negative]