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Question

The value of k such that 3x2+2kx+xk5 have the sum of the zeroes as half of their product,


  1. 4

  2. 2

  3. 3

  4. 1


Solution

The correct option is D

1


Sum of zeros = (2k+1)3

Product of zeros = (k+5)3

Given that,(2k+1)3= -12 (k+5)3

2(2k + 1) = k + 5

4k + 2 = k + 5

3k = 3 ,   k = 1

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