CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of k, such that the equation
2x2+2y26x+8y+k=0 represent a point circle , is

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
25
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
252
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
252
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 252
The given equation of circle is
2x2+2y26x+8y+k=0
x2+y23x+4y+k2=0 [ Dividing both sides by 2 ]
Comparing it with general equation of circle x2+y2+2gx+2fy+c=0, we get
2g=3,2f=4 and c=k2
g=32 and f=2
Center =(g,f)=(32,2)
We know,
Radius (r)=g2+f2c
We know that for point circle radius is 0. r=0
0=(32)2+(2)2k2
0=94+4k2
0=94+4k2
k2=9+164
k2=254
k=252


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Definition of Circle
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon