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Question

The value of (10k=1(sin2πk11icos2πk11)) is

A
1
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B
-1
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C
i
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D
-i
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Solution

The correct option is C i
10k=1(sin2πk11icos2πk11)=10k=1(i2sin2πk11icos2πk11)=i10k=1(cos2πk11+isin2πk11)=i10k=1ei2πk11=i[10k=1ei2πk111]
= -i( sum of 11th roots of unity – 1)
= – i(0 – 1) = i


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