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Question

The value of limmlimn[2+cosm!(n!πx)], xR, where n,mZ is/are

A
0
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B
1
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C
2
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D
3
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Solution

The correct option is D 3
Case 1:
When n!x is a integer
cosm!(n!πx)=(±1)m!=1
(m! is even)
limmlimn[2+cosm!(n!πx)]=2+1 =3

Case 2:
When n!x is a non integer
1<cos(n!πx)<1
limmlimn[2+cosm!(n!πx)]=2+0=2

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