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Question

The value of p and qp0,q0 for which p,q are the roots of the equation: x2+px+q=0 are


A

p = 1, q = -2

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B

p = -1, q = -2

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C

p = -1, q =2

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D

p = 1, q = 2

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Solution

The correct option is C

p = -1, q =2


It is given that p and qp0,q0 are the roots of the equation.

x2+px+q=0

Sum of the roots p + q = -q 2p+q=0 ...(i) Products of roots = pq = q q(p1)=0

p=1,q=0q0

Now substituting p = 1 (i), we get 2(1)+q = 0 2(1)+q=0

q=2


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