Question

The value of $PV$ for 5.6 L of an ideal gas is .......... $RT$ at NTP.

• A. 0.25
• B. 0.3
• C. 1
• D. 0.45

Answer 1

The correct option is A 0.25

NTP is commonly used as a standard condition for testing and documentation of fan capacities: NTP - Normal Temperature and Pressure - is defined as air at ${20}^{o}C$ ($293.15K$, ${68}^{o}F$) and 1 atm ($101.325kPa$) Density $1.204kg/m^3$ ($0.075$ pounds per cubic foot)

At NTP, $P=101325Pa$ and $V=5.6L$ given,so

Gas law is $PV=NRT$

$\Rightarrow \frac{PV}{RT}=\frac{101325\times 5.6\times 0.001}{8.314\times 293.15}=0.23\sim 0.25$