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Question

The value of remainder when 32n+1+2n+2, where n10 is divided by 7 is


A
1
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B
2
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C
0
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D
5
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Solution

The correct option is C 0
32n+1+2n+23(9)n+4(2)n3(2+7)n+4(2)n3(nC0702n+nC1712n1+nC1722n2+)+4(2)n72n+nC1712n1+nC1722n2+

Hence the number is divisible by 7, so the remainder will be 0.

Mathematics

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