Question

The value of $\sec (90-\theta )-\text{cosec}\theta$ is

Answer 1

$\sec ({90}^{\circ }-\theta )=\text{cosec}\theta$

So, $\sec ({90}^{\circ }-\theta )-\text{cosec}\theta$

$=\text{cosec}\theta -\text{cosec}\theta$$=0$