Question

The value of $\sin \theta$ increases as $\theta$ increases in interval (0,$\pi /2$)
Enter $1$ for true and $0$ for false

Answer 1

$\sin 0^{\circ }=0,\sin {45}^{\circ }=\frac{1}{\sqrt{2}},\sin {90}^{\circ }=1$
Thus, as value of $\theta$ increases, value of $\sin \theta$ also increases.