Question

The value of $$\sin \theta$$ increases as $$\theta$$ increases in interval (0,$$\pi/2$$)Enter $$1$$ for true and $$0$$ for false

Solution

$$\sin { { 0 }^{ \circ }=0,\sin { { 45 }^{ \circ }=\frac { 1 }{ \sqrt { 2 } } },\sin { { 90 }^{ \circ }=1 } }$$Thus, as value of $$\theta$$ increases, value of $$\sin\theta$$ also increases. Maths

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