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Question

The value of $$\sin \theta $$ increases as $$\theta $$ increases in interval (0,$$\pi/2$$)
Enter $$1$$ for true and $$0$$ for false


Solution

$$\sin { { 0 }^{ \circ  }=0,\sin { { 45 }^{ \circ  }=\frac { 1 }{ \sqrt { 2 }  }  },\sin { { 90 }^{ \circ  }=1 }  } $$
Thus, as value of $$\theta$$ increases, value of $$\sin\theta$$ also increases. 

Maths

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