The value of -6-6-6- to - is

The correct option is D 3 #160; √(6 + √(6 + √(6 + √( )#10;...... + ∞))) #10; #10; x = √(6 + x) #10; #10; x^2 = 6 + x #10; ...

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Byju's Answer

Standard XII

Mathematics

Definition of Relations

The value of ...

Question

The value of $\sqrt{6 + \sqrt{6 + \sqrt{6 + \sqrt{. . . . to \infty}}}}$ is

6

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- 3

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Solution

The correct option is D $3$
$\sqrt{6 + \sqrt{6 + \sqrt{6 + \sqrt{. . . . . . + \infty}}}}$

$x = \sqrt{6 + x}$

$x^{2} = 6 + x$

$x^{2} - x - 6 = 0$

$x^{2} - 3 x + 2 x - 6 = 0$

$x (x - 3) + 2 (x - 3) = 0$

$(x + 2) (x - 3) = 0$

$x = - 2, 3$

$x = 3, x \neq - 2$

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Q. If

\frac{\sqrt{2}}{\sqrt{6} - \sqrt{2}} - \frac{\sqrt{3}}{\sqrt{6} + \sqrt{2}}

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then value of m is

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The value of $\sqrt{5 + 2 \sqrt{6}}$ is

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The value of √6+√6+√6+√....to ∞ is

The correct option is D 3 √6+√6+√6+√......+∞ x=√6+x x2=6+x x2−x−6=0 x2−3x+2x−6=0 x(x−3)+2(x−3)=0 (x+2)(x−3)=0 x=−2,3 x=3,x≠−2

The value of $\sqrt{6 + \sqrt{6 + \sqrt{6 + \sqrt{. . . . to \infty}}}}$ is

The correct option is D $3$
$\sqrt{6 + \sqrt{6 + \sqrt{6 + \sqrt{. . . . . . + \infty}}}}$

$x = \sqrt{6 + x}$

$x^{2} = 6 + x$

$x^{2} - x - 6 = 0$

$x^{2} - 3 x + 2 x - 6 = 0$

$x (x - 3) + 2 (x - 3) = 0$

$(x + 2) (x - 3) = 0$

$x = - 2, 3$

$x = 3, x \neq - 2$