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Question

The value of 3cosec20sec20 is
  1. 1
  2. 1
  3. 4
  4. 4


Solution

The correct option is C 4
3cosec20sec20
=3sin201cos20
=3cos20sin20sin20cos20=2(32cos2012sin20)sin20cos20
=2(sin60cos20cos60sin20)sin20cos20
=4(sin(6020))2sin20cos20
=4sin40sin40   (2sinθcosθ=sin2θ)=4
 

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