The value of the constant $k$ in coulomb's law is :

9 \times 10^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9 \times 10^{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9 \times 10^{7}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9 \times 10^{9}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $9 \times 10^{9}$
The Coulomb's constant, $k = \frac{1}{4 π ϵ_{0}} = \frac{1}{4 π \times (8.85 \times 10^{- 12})} = 9 \times 10^{9}$

Suggest Corrections

Similar questions

In the given equation the value of $x$ is $\frac{17}{5}$

$9 \times 3^{x} = (27)^{2 x - 5}$

(k)

The value of $(9 \times 10^{- 2}) + (9 \times 10^{3})$ is given by:

10^{- 9} C

Q = 2 C

9 \times 10^{9} N m^{2} C^{- 2}

Join BYJU'S Learning Program