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Question

The value of the determinant ∣ ∣ ∣111nCn1n+1Cnn+2C1nCn2n+1Cn1n+2C2∣ ∣ ∣

A
2
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B
1
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C
0
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D
nCn1
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Solution

The correct option is B 1
=∣ ∣ ∣111nC1n+1C1n+2C1nC2n+1C2n+2C2∣ ∣ ∣
=∣ ∣ ∣111nC1n+1C1n+1C0+n+1C1nC2n+1C2n+1C1+n+1C2∣ ∣ ∣
C3C3C2
=∣ ∣ ∣110nC1n+1C1n+1C0nC2n+1C2n+1C1∣ ∣ ∣

Similarly,
C2C2C1
=∣ ∣ ∣100nC1nC0n+1C0nC2nC1n+1C1∣ ∣ ∣
=nC0×n+1C1n+1C0×nC1=n+1n=1

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