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Question

The value of limx01x3x0tln(1+t)t4+4dt is


A

0

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B

112

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C

124

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D

16

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Solution

The correct option is B

112


limx01x3x0t ln(1+t)t4+4dt[00form]
Applying L' Hospital's rule, we get
limx0x ln(1+x)x4+43x2=limx0ln(1+x)x.13(x4+4)=1.112=112


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