CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The value of limx0(x20sec2t dtx sin x) is
  1. 3
  2. 2
  3. 0
  4. 1


Solution

The correct option is D 1
limx0ddxx20sec2t dtddx(x sin x)=limx0sec2x2.2xsinx+x cos x
By L - Hospital's rule, limx02sec2x2(sinxx+cosx)=2×11+1=1

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More...


People also searched for
QuestionImage
QuestionImage
View More...



footer-image