Question

The value of $x$ in ${\left(\frac{3}{5}\right)}^3\times {\left(\frac{3}{5}\right)}^{-6}={\left(\frac{3}{5}\right)}^{1-2x}$ is _________.

• A. $0$
• B. $1$
• C. $-1$
• D. $2$

Answer 1

The correct option is D $2$

We have,

LHS : $(\frac{3}{5}{)}^{(3+(-6\left)\right)}=(\frac{3}{5}{)}^{-3}$

and R.H.S: $(\frac{3}{5}{)}^{1-2x}$

Comparing powers of LHS & RHS, we get,

$-3=1-2x$

or, $x=\frac{4}{2}=2$