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Question

The value of x satisfying the equation log3(5x2)2log33x+1=1log34 is

A
2
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B
1
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C
3
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D
4
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Solution

The correct option is A 1
log3(5x2)2log33x+1=1log34

L.H.S of the above equation exist when 5x2>0 x>25

and 3x+1>0 x>13
Therefore, x(25,)
log3(5x2)2log33x+1=1log34
log3(5x2)log3(3x+1)+log34=1[mloga=logam]
log34(5x2)(3x+1)=1[loga+logb=log(ab)]
4(5x2)(3x+1)=31=3
20x8=9x+3
x=1
Ans: B

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