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Question

The value of x satisfying the inequation x27x+122x2+4x+5>0 is

A
(3,4)
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B
(2,4)
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C
(,3)(4,)
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D
All real numbers
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Solution

The correct option is C (,3)(4,)
2x2+4x+5 is always positive as D=b24ac=1640=24

(x4)(x3)x2+4x+5>0

Clearly for this equation to be positive x>4 or x<3 as suggested in option C.

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