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Finding Solution of an Equation by Trial and Error Method

The value of ...

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The value of x + Y + Z is 15 and 1 by1/x+1/y+1/z is 5/3 if a,x,y,z,b are in AP ae well as are in HP then a and b are

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x + y + z = 15

a, x, y, z, b

\frac{1}{x} + \frac{1}{y} + \frac{1}{z} = \frac{5}{3}

when a, x, y, z, b are in HP then the quadratic equation whose roots are

\frac{1}{a} a n d \frac{1}{b}

The value of $x + y + x$ is $15,$ if $a, x, y, z$ and bare in AP while the value of $\frac{1}{x} + \frac{1}{y} + \frac{1}{z}$ is $\frac{5}{3}$ ,If, $\frac{1}{a}, \frac{1}{x}, \frac{1}{y}, \frac{1}{z}$ and $\frac{1}{b}$ are in AP . Find the values of a and b.

Q. The value of

x + y + z

15

a, x, y, z, b

are in AP, while the value of

\frac{1}{x} + \frac{1}{y} + \frac{1}{z} i s \frac{5}{3}

a, x, y, z, b

are in H.P. find

| a - b |

Q. The value of

x + y + z i s 15 i f a, x, y, z, b

are in A.P. while the value of

\frac{1}{x} + \frac{1}{y} + \frac{1}{z} i s \frac{5}{3} i f a, x, y, z, b

are in H. P. Then the value of and b are

Q. The value of

x + y + z = 15

a, x, y, z, b

are in A.P, while the value of

\frac{1}{x} + \frac{1}{y} + \frac{1}{z} = \frac{5}{3}

a, x, y, z, b

are in H.P. Find

a \times

b

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Finding Solution of an Equation by Trial and Error Method

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