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Question

The value of xyz is 152or185 according as the series a, x, y, z b is arithmetic or harmonic then ab =

A
1
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B
2
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C
3
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D
4
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Solution

The correct option is C 3
a,x,y,z in A.P.x=3a+b4,y=a+b2,z=a+3b4,xyz=152(3a+b)(a+b)(a+3b)32=152,a,x,y,z b ub H.P.1a,1x,1y,1bin A.P.1x=3a+1b4=a+3b4ab,1y=1a+1b2=a+b2ab,1z=1a+3b4=3a+b4abxyz=32(ab)3(a+3b)(a+b)(3a+b)=185 Multiplying (1)and (2) gives(ab)3=152.185=27

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