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Question

The values of electronegativity of atoms A and B are 1.20 and 4.0 respectively. The percentage of ionic character of A - B bond is
  1. 50 %

  2. 43 %

  3. 72.24%

  4. 55.3 %


Solution

The correct option is C

72.24%


We know that ionic characters
=16[EAEB]+3.5×[EAEB]2
or ionic characters = 72.24%

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