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Question

The van't Hoff factor (i) for a dilute aqueous solution of the strong electrolyte barium hydroxide is :

A
2
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B
3
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C
0
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D
1
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Solution

The correct option is B 3
Ba(OH)2 is a strong electrolyte, so its 100% dissociation occurs in solution.
Van't off factor(i) = Total number of ions present in the solution

Ba(OH)2Ba+2+2OH

So, the total number of ions in the solution is 3.

Hence, option B is correct.

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