Question

The vapor pressure of pure water at ${75}^{\circ }\text{C}$ is 296 torr then the vapor pressure lowering due to 0.1 m solute is

• A. $\text{0}\text{.533 torr}$
• B. $\text{0}\text{.296 torr}$
• C. $\text{0}\text{.333 torr}$
• D. $\text{0}\text{.428 torr}$

Answer 1

The correct option is A $\text{0}\text{.533 torr}$

We know $P_{solv}=X_{\text{solu}}\times p_{solv}^0$

$P_{solv}=\left(\frac{0.1}{0.1+1000/18}\right)\times 296=0.533$ torr