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Question

The variance of first $$20$$ natural numbers is


A
133/4
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B
279/2
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C
133/2
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D
399/4
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Solution

The correct option is A $$133/4$$
Variance of first $$n$$ natural numbers is $$\dfrac {n^{2} - 1}{12}$$
so, for $$n = 20 \rightarrow \dfrac {20^{2} - 1}{12} = \dfrac {133}{4}$$

Mathematics

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